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MySQL的開發(fā)必會(huì)的sql語句

 東西二王 2020-06-25

本文談?wù)凪ySQL的開發(fā)必會(huì)的sql語句

創(chuàng)建數(shù)據(jù)庫

create database db1;

刪除數(shù)據(jù)庫

drop database db1;

創(chuàng)建數(shù)據(jù)表

create table tb1用戶表( id int not null auto_increment primary key, name char(10), department_id int, p_id int, )engine=innodb default charset=utf8;

主鍵(primary key)一個(gè)表只能有一個(gè)主鍵,主鍵可以由一列或者多列組成

外鍵的創(chuàng)建

CREATE TABLE t5 (
                      nid int(11) NOT NULL AUTO_INCREMENT,
                      pid int(11) not NULL,
                      num int(11),
                      primary key(nid,pid) --這里就是把兩列設(shè)置成了主鍵
                    ) ENGINE=InnoDB DEFAULT CHARSET=utf8;

                    create table t6(
                        id int auto_increment primary key,
                        name char(10),
                        id1 int,
                        id2 int,
                        CONSTRAINT fk_t5_t6 foreign key (id1,id2) REFERENCES t1(nid,pid) --這里是設(shè)置外鍵
                    )engine=innodb default charset=utf8;

數(shù)據(jù)行的操作

數(shù)據(jù)的插入

insert into tb1(name,age) values('ax',8); insert into tb12(name,age) select name,age from tb11;

表中的數(shù)據(jù)的刪除

delete from t1;
truncate table t1;
drop table t1
delete from tb1 where id > 10
delete from tb12 where id >=2 or name='alex'

數(shù)據(jù)的更新

update tb1 set name='root' where id > 10

數(shù)據(jù)的查詢

select * from tb;
select id,name from tb;

表結(jié)構(gòu)的查看

show create table t1; desc t1;

其他

  select * from tb12 where id != 1
    select * from tb12 where id in (1,5,12);
    select * from tb12 where id not in (1,5,12);
    select * from tb12 where id in (select id from tb11)
    select * from tb12 where id between 5 and 12;

通配符

select * from tb12 where name like 'a%' select * from tb12 where name like 'a_'

分頁

select * from tb12 limit 10;                    
select * from tb12 limit 0,10;
select * from tb12 limit 10,10;
select * from tb12 limit 20,10;                 
select * from tb12 limit 10 offset 20;

# page = input('請(qǐng)輸入要查看的頁碼')
# page = int(page)
# (page-1) * 10
# select * from tb12 limit 0,10; 1 
# select * from tb12 limit 10,10;2

排序

select * from tb12 order by id desc; 大到小 select * from tb12 order by id asc; 小到大 select * from tb12 order by age desc,id desc; 取后10條數(shù)據(jù) select * from tb12 order by id desc limit 10;

分組

select count(id),max(id),part_id from userinfo5 group by part_id;
聚合函數(shù)有下面幾個(gè):                  
                    count
                    max
                    min
                    sum
                    avg

**** 如果對(duì)于聚合函數(shù)結(jié)果進(jìn)行二次篩選時(shí)?必須使用having ****
select count(id),part_id from userinfo5 group by part_id having count(id) > 1;

select count(id),part_id from userinfo5 where id > 0 group by part_id having count(id) > 1;

自增值設(shè)置

表自增值的設(shè)置

alter table t1 auto_increment=20; -- 這個(gè)就表示從開始20開始算,用上面的show create table t1\G 就可以看到當(dāng)前的值是多少。

基于會(huì)話級(jí)別

-- 查看當(dāng)前的會(huì)話值
show session variables like 'auto_incre%'
-- 設(shè)置會(huì)話步長
set session auto_increment_increment=2;
-- 設(shè)置起始值
set session auto_increment_offset=10;

基于全局設(shè)置

-- 查看全局的設(shè)置值 show global variables like 'auto_inc%'; -- 設(shè)置全局步長值 set global auto_increment_increment=3; -- 設(shè)置起始值 set global auto_increment_offset=11;

sql server 是在創(chuàng)建表的時(shí)候就可以自己設(shè)置,靈活度很高REATE TABLE t5 (nid int(11) NOT NULL AUTO_INCREMENT,pid int(11) NOT NULL,num int(11) DEFAULT NULL,PRIMARY KEY (nid,pid)) ENGINE=InnoDB AUTO_INCREMENT=4, 步長=2 DEFAULT CHARSET=utf8

CREATE TABLE `t6` (

nid int(11) NOT NULL AUTO_INCREMENT,pid int(11) NOT NULL,num int(11) DEFAULT NULL,PRIMARY KEY (nid,pid)) ENGINE=InnoDB AUTO_INCREMENT=4, 步長=20 DEFAULT CHARSET=utf8

唯一索引

create table t1(
    id int,
    num int,
    xx int,
    unique qu1 (num ,xx) -- 意思就是這兩列在一行上面數(shù)據(jù)不能相同,例如都是1,1,就不行
);

唯一索引:約束不能重復(fù)(可以為空)主鍵索引:約束不能重復(fù)(不可以為空)他們的特點(diǎn)都是加速查詢

外鍵一對(duì)一

create table userinfo1( id int auto_increment primary key, name char(10), gender char(10), email varchar(64) )engine=innodb default charset=utf8; create table admin( id int not null auto_increment primary key, username varchar(64) not null, password VARCHAR(64) not null, user_id int not null, unique uq_u1 (user_id), CONSTRAINT fk_admin_u1 FOREIGN key (user_id) REFERENCES userinfo1(id) )engine=innodb default charset=utf8;

外鍵多對(duì)多

示例1:
                用戶表
                相親表

            示例2:
                用戶表
                主機(jī)表
                用戶主機(jī)關(guān)系表
            ===》多對(duì)多

                create table userinfo2(
                    id int auto_increment primary key,
                    name char(10),
                    gender char(10),
                    email varchar(64)
                )engine=innodb default charset=utf8;

                create table host(
                    id int auto_increment primary key,
                    hostname char(64)
                )engine=innodb default charset=utf8;

                create table user2host(
                    id int auto_increment primary key,
                    userid int not null,
                    hostid int not null,
                    unique uq_user_host (userid,hostid),
                    CONSTRAINT fk_u2h_user FOREIGN key (userid) REFERENCES userinfo2(id),
                    CONSTRAINT fk_u2h_host FOREIGN key (hostid) REFERENCES host(id)
                )engine=innodb default charset=utf8;

連表操作

select * from userinfo5,department5 select * from userinfo5,department5 where userinfo5.part_id = department5.id select * from userinfo5 left join department5 on userinfo5.part_id = department5.id select * from department5 left join userinfo5 on userinfo5.part_id = department5.id # userinfo5左邊全部顯示 # select * from userinfo5 right join department5 on userinfo5.part_id = department5.id # department5右邊全部顯示 select * from userinfo5 innder join department5 on userinfo5.part_id = department5.id 將出現(xiàn)null時(shí)一行隱藏 select * from department5 left join userinfo5 on userinfo5.part_id = department5.id left join userinfo6 on userinfo5.part_id = department5.id select score.sid, student.sid from score left join student on score.student_id = student.sid left join course on score.course_id = course.cid left join class on student.class_id = class.cid left join teacher on course.teacher_id=teacher.ti select count(id) from userinfo5;

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