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參見英文答案 > When to use single quotes, double quotes, and back ticks in MySQL????????????????????????????????????12個
我有一個代碼,與mysql工作正常,但已切換到mysqli它不再運行.數(shù)據(jù)在選擇按鈕的表格中正確顯示,它看起來像我得到保存gif(因為正在調(diào)用Ajax),但是更新語句不會更新數(shù)據(jù)庫.
似乎沒有工作的部分是saveedit.php：
<?php
require_once("dbcontroller.php");
$db_handle = new DBController();
$column=$_POST['column'];
$value=$_POST['value'];
$id=$_POST['id'];
$sql = "UPDATE php_interview_questions SET `$column` = '$value' WHERE id=$id)";
$result = mysqli_query ($conn, $sql) or die(mysqli_error ($dbc));
?>
主頁是
<?php
require_once("dbcontroller.php");
$db_handle = new DBController();
$sql = "SELECT * from php_interview_questions";
$faq = $db_handle->runQuery($sql);
?>
<html>
<head>
<title>PHP MySQL Inline Editing using jQuery Ajax</title>
<script src="http://code./jquery-1.10.2.js"></script>
<script>
function showEdit(editableObj) {
$(editableObj).css("background","#FFF");
}
function saveToDatabase(editableObj,column,id) {
$(editableObj).css("background","#FFF url(loaderIcon.gif) no-repeat right");
$.ajax({
url: "saveedit.php",
type: "POST",
data:'column=' column '&editval=' editableObj.innerHTML '&id=' id,
success: function(data){
$(editableObj).css("background","#FDFDFD");
}
});
}
</script>
</head>
<body>
<table class="tbl-qa">
<thead>
<tr>
<th class="table-header" width="10%">Q.No.</th>
<th class="table-header">Question</th>
<th class="table-header">Answer</th>
</tr>
</thead>
<tbody>
<?php
foreach($faq as $k=>$v) {
?>
<tr class="table-row">
<td><?php echo $k 1; ?></td>
<td contenteditable="true" onBlur="saveToDatabase(this,'question','<?php echo $faq[$k]["id"]; ?>')" onClick="showEdit(this);"><?php echo $faq[$k]["question"]; ?></td>
<td contenteditable="true" onBlur="saveToDatabase(this,'answer','<?php echo $faq[$k]["id"]; ?>')" onClick="showEdit(this);"><?php echo $faq[$k]["answer"]; ?></td>
</tr>
<?php
}
?>
</tbody>
</table>
</body>
</html>
使用db_controller.php連接到數(shù)據(jù)庫并處理結(jié)果集創(chuàng)建(數(shù)據(jù)庫連接詳細(xì)信息位于此處未發(fā)布的文件中)：
function __construct() {
$conn = $this->connectDB();
if(!empty($conn)) {
$this->selectDB($conn);
}
}
function connectDB() {
$conn = mysqli_connect($this->host,$this->user,$this->password);
return $conn;
}
function selectDB($conn) {
mysqli_select_db($conn, $this->database);
}
function runQuery($query) {
$conn = mysqli_connect($this->host,$this->user,$this->password);
mysqli_select_db($conn, $this->database);
$result = mysqli_query($conn, $query)or die(mysqli_error($conn));
while($row=mysqli_fetch_assoc($result)) {
$resultset[] = $row;
}
if(!empty($resultset))
return $resultset;
}
function numRows($query) {
$result = mysqli_query($conn, $query);
$rowcount = mysqli_num_rows($result);
return $rowcount;
}
}
?>
我現(xiàn)在已經(jīng)將dbcontroller更改為以下內(nèi)容以簡化并嘗試拋出錯誤但仍然沒有得到任何結(jié)果
<?php
class DBController {
private $host = "***********";
private $user = "***********";
private $password = "**********";
private $database = "************";
function __construct() {
$conn = mysqli_connect($this->host,$this->user,$this->password,$this->database) OR die (mysqli_connect_error());
}
function runQuery($query) {
$conn = mysqli_connect($this->host,$this->user,$this->password);
mysqli_select_db($conn, $this->database);
$result = mysqli_query($conn, $query)or die(mysqli_error($conn));
while($row=mysqli_fetch_assoc($result)) {
$resultset[] = $row;
}
if(!empty($resultset))
return $resultset;
}
function numRows($query) {
$result = mysqli_query($conn, $query);
$rowcount = mysqli_num_rows($result);
return $rowcount;
}
}
?
> 解決方法: 刪除列周圍的單個qoutes名稱：
$sql = "UPDATE php_interview_questions SET $column = '$value' WHERE id=$id)";
或者,如果列中有特殊字符,請使用反引號來逃避它們.
$sql = "UPDATE php_interview_questions SET `$column` = '$value' WHERE id=$id)";
如果id是一個數(shù)值,你也不需要單個qoutes. 來源：https://www./content-2-262651.html
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