|
107期2478=01開(kāi)415對(duì) 108期3569=01開(kāi)758對(duì) 109期3578=01開(kāi)474對(duì) 110期0278=01開(kāi)988對(duì) 111期4689=01開(kāi)871對(duì) 112期3578=01開(kāi)451對(duì) 113期2569=01開(kāi)405對(duì) 114期2569=01開(kāi)844對(duì) 115期2478=01開(kāi)598對(duì) 116期4689=01開(kāi)771對(duì) 117期0358=01開(kāi)716對(duì) 118期2478=01開(kāi)607對(duì) 119期2478=01開(kāi)079對(duì) 120期3679=01開(kāi)748對(duì) 121期3578=01開(kāi)227對(duì) 122期4689=01開(kāi)274對(duì) 123期0278=01開(kāi)240錯(cuò) 124期2478=01開(kāi)599對(duì) 125期1356=01開(kāi)259對(duì) 126期3578=01開(kāi)971對(duì) 127期3679=01開(kāi)097錯(cuò) 128期3679=01開(kāi)313對(duì) 129期3578=01開(kāi)055對(duì) 130期3679=01開(kāi)218對(duì) 131期0278=01開(kāi)471對(duì) 132期0278=01開(kāi)685對(duì) 133期4568=01開(kāi)001對(duì) 134期4568=01開(kāi)661對(duì) 135期0278=01開(kāi)231對(duì) 我只能看出應(yīng)該是固定的4碼卻怎么也破解不出來(lái)是什么對(duì)應(yīng)的 破解方法就是上期開(kāi)獎(jiǎng)號(hào)和尾加跨度的得數(shù)取個(gè)位對(duì)應(yīng)4碼=01 0--2478 1--0358 2--4568 3--3578 4--2569 5--3679 6--4689 7--1356 8--0278 9--3578 例如134期開(kāi)661 和尾3 跨度5 3加5就等于8 8對(duì)應(yīng)0278 那么135期對(duì)應(yīng)4碼0278=01 其他期數(shù)開(kāi)獎(jiǎng)號(hào)以此類(lèi)推。 |
|
|
